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Question
the formula below gives the area of a semi-circle, \\(a\\), with a radius of \\(r\\).
\\a = \frac{1}{2}\pi r^2\\
solve the formula for the radius.
\\(r = \frac{1}{2}\sqrt{\frac{\pi}{a}}\\)
\\(r = \sqrt{\frac{\pi}{2a}}\\)
\\(r = 2\sqrt{\frac{a}{\pi}}\\)
\\(r = \sqrt{\frac{2a}{\pi}}\\)
Isolate the term containing r
$$
LATEXBLOCK0
$$
Divide by pi
$$
r^2 = \frac{2A}{\pi}
$$
Take the square root
$$
r = \sqrt{\frac{2A}{\pi}}
$$
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- (A) \(r = \frac{1}{2}\sqrt{\frac{\pi}{A}}\)
- (B) \(r = \sqrt{\frac{\pi}{2A}}\)
- (C) \(r = 2\sqrt{\frac{A}{\pi}}\)
- (D) \(r = \sqrt{\frac{2A}{\pi}}\) (Correct answer)