Question

the formula for the area of a trapezoid is ( a=\frac{1}{2}(b_1 + b_2)h ).
the height, ( h ), of the trapezoid may be expressed as
(1) ( 2a - b_1 - b_2 )
(2) ( \frac{2a - b_1}{p^2} )
(3) ( \frac{1}{2}a - b_1 - b_2 )
(4) ( \frac{2a}{b_1 + b_2} )

Explanation:

Step1: Rearrange the formula

Given \(A=\frac{1}{2}(b_1 + b_2)h\), multiply both sides by \(2\) to get \(2A=(b_1 + b_2)h\).

Step2: Solve for \(h\)

Divide both sides by \((b_1 + b_2)\), so \(h=\frac{2A}{b_1 + b_2}\).

Answer:

\(\frac{2A}{b_1 + b_2}\) (Option (4) if we assume the options are labeled as in the problem statement where (4) is \(\frac{2A}{b_1 + b_2}\))