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for the following right triangle, find the side length x. round your an…

Question

for the following right triangle, find the side length x. round your answer to the nearest hundredth.

Explanation:

Step1: Apply Pythagorean theorem

For a right triangle, \(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse, and \(a\), \(b\) are the legs. Here, hypotenuse \(c = 15\), one leg \(a = 12\), the other leg \(b = x\). So \(12^2 + x^2 = 15^2\).

Step2: Solve for \(x^2\)

Calculate \(12^2 = 144\), \(15^2 = 225\). Then \(x^2 = 225 - 144 = 81\)? Wait, no, wait, wait. Wait, no, the hypotenuse is the longest side. Wait, 15 is longer than 12, so 15 is hypotenuse. Wait, but 12 and x are legs, 15 is hypotenuse. Wait, but \(12^2 + x^2 = 15^2\), so \(x^2 = 15^2 - 12^2 = 225 - 144 = 81\)? But 81 is a perfect square, \(x = \sqrt{81} = 9\)? Wait, but that's a whole number. Wait, maybe I misread the triangle. Wait, the right angle is between 12 and x, so the hypotenuse is 15. So Pythagorean theorem: \(12^2 + x^2 = 15^2\). So \(x^2 = 225 - 144 = 81\), so \(x = \sqrt{81} = 9.00\) when rounded to nearest hundredth.

Answer:

9.00