Question

the following data represent the concentration of dissolved organic carbon (mg/l) collected from 20 samples of organic soil. assume that the population is normally distributed. complete parts (a) through (c) on the right. 22.49 29.80 27.10 16.51 15.72 8.81 5.20 20.46 14.90 33.67 30.91 14.86 15.42 15.35 9.72 19.80 14.86 8.09 11.40 18.30 (a) find the sample mean. the sample mean is (round to two decimal places as needed.)

Explanation:

Step1: Sum all data values

$$22.49 + 29.80+27.10 + 16.51+15.72+8.81 + 5.20+20.46+14.90+33.67+30.91+14.86+15.42+15.35+9.72+19.80+14.86+8.09+11.40+18.30 = 360.33$$

Step2: Divide by the number of samples

The number of samples \(n = 20\). The sample mean \(\bar{x}=\frac{360.33}{20}=18.0165\)

Step3: Round to two decimal places

Rounding \(18.0165\) to two decimal places gives \(18.02\)

Answer:

\(18.02\)