Question

first, find the slope of the line.
m = 3
next, find the y-intercept of the line.
b =
there is a coordinate grid with a line plotted and a number pad image on the left side

Explanation:

Step1: Identify the \( y \) - intercept

The \( y \) - intercept \( b \) is the \( y \) - coordinate of the point where the line crosses the \( y \) - axis (i.e., when \( x = 0 \)).
From the graph, when \( x = 0 \), the line intersects the \( y \) - axis at \( y=-1 \).
So \( b=-1 \).

Answer:

• For the slope \( m \): Given as \( 3 \) (but let's verify with the graph). Wait, maybe a mis - read, let's recalculate. The two points on the line: Let's take \( (-2,0) \) and \( (0, - 1) \)? Wait, no, let's check the axes. Wait, the \( x \) - axis and \( y \) - axis: Let's find two points. Let's say when \( x=-2,y = 0 \) and when \( x = 0,y=-1 \)? No, wait the slope formula is \( m=\frac{y_2 - y_1}{x_2 - x_1} \). Wait, maybe the correct slope calculation: Let's take two points. Suppose the line passes through \( (-2,0) \) and \( (0, - 1) \), then \( m=\frac{-1 - 0}{0-(-2)}=\frac{-1}{2}=-0.5 \). But the given \( m = 3 \) is wrong. Wait, maybe the user made a typo. Now for the \( y \) - intercept \( b \): The \( y \) - intercept is the value of \( y \) when \( x = 0 \). From the graph, when \( x = 0 \), the line crosses the \( y \) - axis at \( y=-1 \). So \( b=-1 \).

Wait, maybe I misread the graph. Let's re - examine. The graph has a line. Let's find two clear points. Let's take \( (x_1,y_1)=(-2,0) \) and \( (x_2,y_2)=(2, - 2) \). Then the slope \( m=\frac{-2 - 0}{2-(-2)}=\frac{-2}{4}=-\frac{1}{2} \). And the \( y \) - intercept: when \( x = 0 \), \( y=-1 \), so \( b=-1 \).

But according to the initial given \( m = 3 \), that seems incorrect. Assuming we need to find \( b \) from the graph, the \( y \) - intercept \( b=-1 \).