Question

finding unknown angle measures
which shows the angle addition postulate?
∠pqs + ∠sqr = ∠pqr
∠pqs + ∠sqr = 180°
∠pqs - ∠sqr = ∠pqr
∠pqs + ∠pqr = ∠sqr
question 1 of 8

Explanation:

The Angle Addition Postulate states that if a point (here, \( S \)) lies in the interior of an angle ( \( \angle PQR \) ), then the sum of the two smaller angles ( \( \angle PQS \) and \( \angle SQR \)) formed is equal to the measure of the larger angle ( \( \angle PQR \) ). So \( \angle PQS + \angle SQR = \angle PQR \) follows this postulate. The other options either use subtraction, incorrect angle sums, or sum to \( 180^\circ \) (which isn't indicated here as a straight angle situation for these angles).

Answer:

\( \boldsymbol{\angle PQS + \angle SQR = \angle PQR} \) (the first option: \( \angle PQS + \angle SQR = \angle PQR \))