Question

find the vertex of the parabola $y = x^2 + 9$. simplify both coordinates and write them as proper fractions, improper fractions, or integers. (\boxed{\quad}, \boxed{\quad}) submit

Explanation:

Step1: Recall vertex form of parabola

The vertex form of a parabola is $y=a(x-h)^2+k$, where $(h,k)$ is the vertex.

Step2: Rewrite given equation

Rewrite $y=x^2+9$ as $y=1(x-0)^2+9$.

Step3: Identify h and k values

Here, $h=0$ and $k=9$.

Answer:

$(0, 9)$