Question

find the value of each limit.

1. $lim_{x

ightarrow - 3}(2x^{2}+x - 5)$

Explanation:

Step1: Substitute x value

Substitute \(x = - 3\) into \(2x^{2}+x - 5\).

$$2(-3)^{2}+(-3)-5$$

Step2: Calculate powers

First, calculate \((-3)^{2}=9\).

$$2\times9+(-3)-5$$

Step3: Multiply

Multiply \(2\times9 = 18\).

$$18+(-3)-5$$

Step4: Simplify addition and subtraction

$$18 - 3-5=10$$

Answer:

\(10\)