QUESTION IMAGE
Question
find the value of x.
○ x = 2
○ x = 3
○ x = 33
○ x = 52
(45x)° at q-r, (25x)° at t, (57 + x)° at r-s, triangle t-r-s with q-r-s on a straight line
Step1: Sum of angles in triangle
Sum of angles in $\triangle TRS$ is $180^\circ$: $25x + \angle TRS + \angle TSR = 180^\circ$.
Step2: Linear pair angles
$\angle TRS = 180^\circ - 45x$, $\angle TSR = 180^\circ - (57 + x)$.
Step3: Substitute into triangle sum
$25x + (180 - 45x) + (180 - 57 - x) = 180$.
Step4: Simplify equation
$25x + 180 - 45x + 123 - x = 180$ → $-21x + 303 = 180$ → $-21x = -123$ → $x = 3$.
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B. x = 3