Question

1. if \\(a = 6\\), \\(b = 3\\) and \\(c = 20\\) find the value of \\(x\\)

a) \\(x = 4 + a - b\\)
b) \\(x = 3b - 7\\)
c) \\(x = 6 + \frac{c}{4}\\)
d) \\(a = 15 - x\\)
e) \\(c = x - 37 + 5b\\)
f) \\(b = 39 - 4x\\)

Explanation:

Identify the given values and equations

The image is upside down. Let's read the text of Question 3:
"3. If \(a = 6\), \(b = 3\) and \(c = 20\) find the value of \(x\)"

We have several sub-parts (a to f) with equations relating \(x\) to \(a\), \(b\), and \(c\):

• a) \(x = 4 + a - b\)
• b) \(x = 3b - 7\)
• c) \(x = 6 + \frac{c}{4}\)
• d) \(a = 15 - x\)
• e) \(c = x - 37 + 5b\)
• f) \(b = 39 - 4x\)

Let's solve for \(x\) in each sub-part by substituting the given values: \(a = 6\), \(b = 3\), \(c = 20\).

Substitute and calculate for each part

• For a):

$$ x = 4 + 6 - 3 = 7 $$

• For b):

$$ x = 3(3) - 7 = 9 - 7 = 2 $$

• For c):

$$ x = 6 + \frac{20}{4} = 6 + 5 = 11 $$

• For d):

$$ 6 = 15 - x \implies x = 15 - 6 = 9 $$

• For e):

$$ 20 = x - 37 + 5(3) \implies 20 = x - 37 + 15 \implies 20 = x - 22 \implies x = 42 $$

• For f):

$$ 3 = 39 - 4x \implies 4x = 39 - 3 \implies 4x = 36 \implies x = 9 $$

Summarize the results

The values of \(x\) for each part are:

• a) \(x = 7\)
• b) \(x = 2\)
• c) \(x = 11\)
• d) \(x = 9\)
• e) \(x = 42\)
• f) \(x = 9\)

Answer:

• a) \(x = 7\)
• b) \(x = 2\)
• c) \(x = 11\)
• d) \(x = 9\)
• e) \(x = 42\)
• f) \(x = 9\)