QUESTION IMAGE
Question
- find the value of x. 13 39
Step1: Apply the tangent - secant segment theorem
If a tangent segment and a secant segment are drawn to a circle from an external point, then \(x^{2}=13\times(13 + 39)\).
Step2: Simplify the right - hand side of the equation
First, calculate \(13+39 = 52\). Then \(13\times52=676\). So the equation becomes \(x^{2}=676\).
Step3: Solve for \(x\)
Take the square root of both sides. Since \(x\) represents a length (a non - negative quantity), \(x=\sqrt{676}\).
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\(x = 26\)