find two consecutive whole numbers that \$\\sqrt{106}\$ lies between.

$find two consecutive whole numbers that \$\\sqrt{106}\$ lies between.$

find two consecutive whole numbers that \$\sqrt{106}\$ lies between.

We know that $10^2 = 100$ and $11^2 = 121$.

Since $10^2 = 100 < 106 < 121 = 11^2$, taking square roots (since square root is an increasing function), we get $10 < \sqrt{106} < 11$.

10 and 11