Question

find two consecutive whole numbers that \\(\sqrt{73}\\) lies between.
\\(\square\\) and \\(\square\\)

Explanation:

Step1: Find squares of whole numbers

Calculate squares near 73: $8^2 = 64$, $9^2 = 81$

Step2: Compare to $\sqrt{73}$

Since $64 < 73 < 81$, take square roots: $\sqrt{64} < \sqrt{73} < \sqrt{81}$

Step3: Simplify square roots

$\sqrt{64}=8$, $\sqrt{81}=9$, so $8 < \sqrt{73} < 9$

Answer:

8 and 9