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Question
find the surface area of this square pyramid. surface area of a pyramid la = 2bl sa = la + b sa = ? cm²
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First, find the lateral area (LA) using \( LA = 2bl \). Here, \( b = 5 \) cm (base edge) and \( l = 8 \) cm (slant height). So \( LA = 2\times5\times8 = 80 \) \( \text{cm}^2 \). Then, find the base area (B) of the square base: \( B = 5\times5 = 25 \) \( \text{cm}^2 \). Now, find the surface area (SA) using \( SA = LA + B \), so \( SA = 80 + 25 = 105 \) \( \text{cm}^2 \).
105