Question

1. find the sum of the measures of the exterior angles of a 52 - gon. 360° 9360° 9000° 520°

Explanation:

Step1: Recall the exterior angle sum theorem

The sum of the exterior angles of any convex polygon (one at each vertex) is always \(360^\circ\), regardless of the number of sides the polygon has.

Step2: Apply the theorem to a 52 - gon

Since a 52 - gon is a polygon, by the exterior angle sum theorem, the sum of its exterior angles (one at each vertex) is \(360^\circ\).

Answer:

\(360^\circ\) (corresponding to the first option: \(360^\circ\))