Question

find the solution of the system of equations.\

$$\begin{cases}3x + 5y = 26\\\\-3x - 2y = -14\\end{cases}$$

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show your work here\
x = \
y = \
check

Explanation:

Step1: Add the two equations

Add the equations \(3x + 5y = 26\) and \(-3x - 2y = -14\) together. The \(3x\) and \(-3x\) will cancel out.

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Step2: Solve for y

Divide both sides of the equation \(3y = 12\) by 3.

$$ y=\frac{12}{3}=4 $$

Step3: Substitute y into one equation

Substitute \(y = 4\) into the first equation \(3x + 5y = 26\).

$$ 3x+5\times4 = 26\\ 3x + 20 = 26 $$

Step4: Solve for x

Subtract 20 from both sides: \(3x=26 - 20=6\). Then divide both sides by 3: \(x = \frac{6}{3}=2\)

Answer:

\(x = 2\), \(y = 4\)