Question

find the z - score such that the area under the standard normal curve to the right is 0.11. the approximate z - score that corresponds to a right tail area of 0.11 is (round to two decimal places as needed.)

Explanation:

Step1: Use the property of the standard normal curve

The total area under the standard normal curve is \(1\). If the area to the right of \(z\) is \(A = 0.11\), then the area to the left of \(z\) is \(P(Z<z)=1 - 0.11=0.89\).

Step2: Look up the \(z\) - value in the standard normal table

We look for the value closest to \(0.89\) in the body of the standard - normal table (the \(z\) - table).
Looking at the standard normal table:
The value \(0.8888\) corresponds to \(z = 1.22\) and the value \(0.8907\) corresponds to \(z = 1.23\).
Since \(0.89\) is closer to \(0.8907\) than to \(0.8888\).

Answer:

\(1.23\)