find the real solution of the following radical equation.

\\sqrt{z + 7} = 6\

\z = ?\

Question

find the real solution of the following radical equation.

\\sqrt{z + 7} = 6\

\z = ?\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Radical Equations", "Solving Radical Equations" ], "new_concepts": [], "current_concepts": [ "Radical Equations", "Solving Radical Equations" ] } ## Square both sides of the equation $$ \begin{aligned} \sqrt{z + 7} &= 6 \ (\sqrt{z + 7})^2 &= 6^2 \ z + 7 &= 36 \end{aligned} $$ ## Solve for z $$ \begin{aligned} z &= 36 - 7 \ z &= 29 \end{aligned} $$ ## Verify the solution $$ \begin{aligned} \sqrt{29 + 7} &= \sqrt{36} = 6 \end{aligned} $$ Find the real solution of the following radical equation. $$\sqrt{z + 7} = 6$$ $z =$ 29 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Solving Radical Equations" ] }

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Square both sides of the equation

Solve for z

Verify the solution

Answer: