Question

find the perimeter. yd 15yd 2yd 6yd 8yd 3yd

Explanation:

Step1: Calculate the sum of the lengths of the outer sides

The outer length is \(15\) yd. The two vertical outer - side lengths: \(2 + 6+3=11\) yd.
The sum of the outer - side lengths (excluding the indented part) forms a rectangle - like outer frame. The perimeter of a rectangle has the formula \(P=(l + w)\times2\), where \(l = 15\) yd and \(w = 11\) yd. But we also need to add the two indented sides of length \(8\) yd.
The sum of the outer - side lengths (using the concept of translation of line segments) without considering the indented part: \((15+(2 + 6+3))\times2=(15 + 11)\times2=26\times2 = 52\) yd.

Step2: Add the lengths of the indented sides

The indented sides each have a length of \(8\) yd. So we add \(8\times2\) yd to the previous sum.
\(52+8\times2=52 + 16\)

Answer:

\(68\)