Question

find the perimeter of the quadrilateral.
if \\(x = 2\\), the perimeter is inches.

left side: \\(31\text{ in.}\\)
top side: \\((4x^2 + 8x)\text{ in.}\\)
right side: \\((3x^2 - 5x + 20)\text{ in.}\\)
bottom side: \\((7x + 30)\text{ in.}\\)

Explanation:

Write the polynomial expression for the perimeter

$$ P(x) = (4x^2 + 8x) + (3x^2 - 5x + 20) + (7x + 30) + 31 $$

$$ P(x) = 7x^2 + 10x + 81 $$

Evaluate the perimeter at x = 2

$$ P(2) = 7(2)^2 + 10(2) + 81 $$

$$ P(2) = 7(4) + 20 + 81 = 28 + 20 + 81 = 129 $$

Answer:

Find the perimeter of the quadrilateral.
If \(x = 2\), the perimeter is <blank>129</blank> inches.