Question

find the perimeter of the figure below, composed of an isoceles trapezoid and one semicircle. rounded to the nearest tenths place

Explanation:

Step1: Calculate the arc length of the semicircle

The formula for the circumference of a circle is \(C = \pi d\). For a semicircle, the arc length \(l=\frac{1}{2}\pi d\). Given \(d = 2\), then \(l=\frac{1}{2}\times\pi\times2=\pi\approx3.14\)

Step2: Sum up the lengths of the non - semicircle sides

The lengths of the non - semicircle sides are \(14\), \(4\), and \(4\). Their sum is \(14 + 4+4=22\)

Step3: Calculate the perimeter

The perimeter \(P\) of the figure is the sum of the arc length of the semicircle and the sum of the non - semicircle sides. \(P=22 + 3.14=25.14\approx25.1\)

Answer:

\(25.1\)