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find the limit, if it exists. (if an answer does not exist, enter dne.)…

Question

find the limit, if it exists. (if an answer does not exist, enter dne.)
\\( \lim _ { x \
ightarrow \infty } \left( 3 + \frac { 8 } { x } \
ight) \\)

Explanation:

Step1: Apply limit laws

We know that \(\lim_{x
ightarrow\infty}(a + b)=\lim_{x
ightarrow\infty}a+\lim_{x
ightarrow\infty}b\). So \(\lim_{x
ightarrow\infty}(3+\frac{8}{x})=\lim_{x
ightarrow\infty}3+\lim_{x
ightarrow\infty}\frac{8}{x}\).

Step2: Evaluate \(\lim_{x

ightarrow\infty}3\)
The limit of a constant \(c\) as \(x
ightarrow\infty\) is \(c\). So \(\lim_{x
ightarrow\infty}3 = 3\).

Step3: Evaluate \(\lim_{x

ightarrow\infty}\frac{8}{x}\)
As \(x
ightarrow\infty\), \(\frac{8}{x}
ightarrow0\). Mathematically, \(\lim_{x
ightarrow\infty}\frac{8}{x}=8\lim_{x
ightarrow\infty}\frac{1}{x}\). Since \(\lim_{x
ightarrow\infty}\frac{1}{x}=0\), then \(8\lim_{x
ightarrow\infty}\frac{1}{x}=0\).

Step4: Sum the results

\(\lim_{x
ightarrow\infty}(3+\frac{8}{x})=\lim_{x
ightarrow\infty}3+\lim_{x
ightarrow\infty}\frac{8}{x}=3 + 0\).

Answer:

\(3\)