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find the lengths of the segments with variable expressions. ef = 13 ad …

Question

find the lengths of the segments with variable expressions.
ef = 13
ad = \square

Explanation:

Step1: Identify midsegment property

EF is midsegment, so $EF=\frac{AD+BC}{2}$

Step2: Substitute known values

$13=\frac{(x-6)+(2x-7)}{2}$

Step3: Solve for x

Multiply both sides by 2: $26=3x-13$ → $3x=39$ → $x=13$

Step4: Calculate AD

$AD=x-6=13-6=7$

Answer:

7