QUESTION IMAGE
Question
find the inverse for the function:
\\f(x) = 3x - 21\\
\\f^{-1}(x) = \frac{x}{?} + \\
<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"blank_filling_formatter",
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"concepts_used": [
"Inverse Functions",
"Finding Inverse Algebraically"
],
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</pre_analysis>
<reasoning>
Replace f(x) with y
Using the Inverse Functions knowledge point
\[
y = 3x - 21
\]
Swap x and y
Using the Inverse Functions knowledge point
\[
x = 3y - 21
\]
Solve for y
Using the Finding Inverse Algebraically knowledge point
\[
\]
Express as inverse function
Using the Finding Inverse Algebraically knowledge point
\[
f^{-1}(x) = \frac{x}{3} + 7
\]
</reasoning>
<answer>
Find the inverse for the function:
\(f(x) = 3x - 21\)
\(f^{-1}(x) = \frac{x}{<blank>3</blank>} + <blank>7</blank>\)
</answer>
<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Finding Inverse Algebraically"
]
}
</post_analysis>
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<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"blank_filling_formatter",
"explain_then_answer",
"tutor",
"mastery_adaptive_brevity"
],
"needs_drawing": false,
"concepts_used": [
"Inverse Functions",
"Finding Inverse Algebraically"
],
"new_concepts": [],
"current_concepts": [
"Inverse Functions",
"Finding Inverse Algebraically"
]
}
</pre_analysis>
<reasoning>
Replace f(x) with y
Using the Inverse Functions knowledge point
\[
y = 3x - 21
\]
Swap x and y
Using the Inverse Functions knowledge point
\[
x = 3y - 21
\]
Solve for y
Using the Finding Inverse Algebraically knowledge point
\[
\]
Express as inverse function
Using the Finding Inverse Algebraically knowledge point
\[
f^{-1}(x) = \frac{x}{3} + 7
\]
</reasoning>
<answer>
Find the inverse for the function:
\(f(x) = 3x - 21\)
\(f^{-1}(x) = \frac{x}{<blank>3</blank>} + <blank>7</blank>\)
</answer>
<post_analysis>
{
"subject": "Mathematics",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Mathematics",
"Algebra",
"Finding Inverse Algebraically"
]
}
</post_analysis>