Question

find: \sin b\
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$$\begin{array}{c|c|c|c} \\frac{11}{60} & \\frac{60}{11} & \\frac{11}{61} & \\frac{60}{61} \\end{array}$$

Explanation:

Step1: Recall Sine Definition

In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify Sides for $\angle B$

For $\angle B$, the opposite side is $60$ (length of side opposite $\angle B$), and the hypotenuse is $61$ (longest side of the right triangle).

Step3: Calculate $\sin B$

Using the sine formula: $\sin B = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{60}{61}$.

Answer:

$\frac{60}{61}$ (corresponding to the last option, e.g., if options are labeled as A: $\frac{11}{60}$, B: $\frac{60}{11}$, C: $\frac{11}{61}$, D: $\frac{60}{61}$, then the answer is D. $\frac{60}{61}$)