Question

find each difference.
$(-6s^2 + 12s - 8) - (3s^2 + 8s - 6) =$
$\circ$ $-9s^2 + 4s - 14$
$\circ$ $-9s^2 + 4s - 2$
$\circ$ $-9s^2 + 20s - 14$
$\circ$ $-9s^2 + 20s - 2$
done

Explanation:

Step1: Distribute the negative sign

To subtract the second polynomial from the first, we distribute the negative sign to each term in the second polynomial:
\((-6s^2 + 12s - 8) - (3s^2 + 8s - 6) = -6s^2 + 12s - 8 - 3s^2 - 8s + 6\)

Step2: Combine like terms for \(s^2\) terms

Combine the \(s^2\) terms: \(-6s^2 - 3s^2 = -9s^2\)

Step3: Combine like terms for \(s\) terms

Combine the \(s\) terms: \(12s - 8s = 4s\)

Step4: Combine like terms for constant terms

Combine the constant terms: \(-8 + 6 = -2\)

Step5: Write the final polynomial

Putting it all together, we get: \(-9s^2 + 4s - 2\)

Answer:

\(-9s^2 + 4s - 2\) (corresponding to the option \(-9s^2 + 4s - 2\))