Question

find the distance between a(-8,10) and b(-6,7). (3pts)
round to the nearest 10th
distance =

Explanation:

Step1: Recall distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-8,y_1 = 10,x_2=-6,y_2 = 7$.

Step2: Substitute values

$d=\sqrt{(-6-(-8))^2+(7 - 10)^2}=\sqrt{( - 6 + 8)^2+(7 - 10)^2}=\sqrt{(2)^2+(-3)^2}$.

Step3: Calculate squares and sum

$\sqrt{(2)^2+(-3)^2}=\sqrt{4 + 9}=\sqrt{13}$.

Step4: Round result

$\sqrt{13}\approx3.6$ (rounded to the nearest tenth).

Answer:

$3.6$