find the derivative of $f(x)=\\frac{x^{2}}{x^{3}}$.

$find the derivative of $f(x)=\\frac{x^{2}}{x^{3}}$.$

find the derivative of $f(x)=\frac{x^{2}}{x^{3}}$.

$$f(x)=\frac{x^{2}}{x^{3}}=x^{2 - 3}=x^{-1}$$

The power rule for differentiation is $\frac{d}{dx}(x^{n})=nx^{n - 1}$. For $n=-1$, we have:
$$f^{\prime}(x)=(-1)x^{-1-1}$$

$$f^{\prime}(x)=-x^{-2}=-\frac{1}{x^{2}}$$

$-\frac{1}{x^{2}}$