find the area under the curve $y = \\frac{6}{x}$ over the interval $1, …

$find the area under the curve $y = \\frac{6}{x}$ over the interval $1, …$

find the area under the curve $y = \frac{6}{x}$ over the interval $1, 3$

The area under $ y = \frac{6}{x} $ from [1,3] is $ \int_{1}^{3} \frac{6}{x} dx $

Antiderivative of $ \frac{6}{x} $ is $ 6\ln|x| $. Evaluate from 1 to 3:
$ 6\ln(3) - 6\ln(1) = 6\ln(3) - 0 = 6\ln(3) $

$ 6\ln 3 $