QUESTION IMAGE
Question
find the area of this triangle. 65° 18 8 square units round to the nearest hundredth.
Step1: Recall the formula for the area of a triangle with two sides and included angle
The formula is \( A=\frac{1}{2}ab\sin C\), where \(a\) and \(b\) are the lengths of two sides and \(C\) is the included angle. Here \(a = 8\), \(b=18\), and \(C = 65^{\circ}\).
Step2: Substitute the values into the formula
\(A=\frac{1}{2}\times8\times18\times\sin(65^{\circ})\). First, calculate \(\frac{1}{2}\times8\times18=72\). Then, find \(\sin(65^{\circ})\approx0.9063\).
Step3: Multiply the results
\(A = 72\times0.9063=65.2536\).
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\(65.25\)