Question

find the area of a trapezoid with bases 5 cm and 11 cm, and a height of 7 cm.

Explanation:

Step1: Recall the formula for the area of a trapezoid

The formula for the area of a trapezoid is \(A=\frac{(b_1 + b_2)h}{2}\), where \(b_1\) and \(b_2\) are the lengths of the bases and \(h\) is the height.

Step2: Substitute the given values into the formula

Given \(b_1 = 5\mathrm{cm}\), \(b_2=11\mathrm{cm}\), and \(h = 7\mathrm{cm}\). Then \(A=\frac{(5 + 11)\times7}{2}\).
First, calculate the sum of the bases: \(5+11 = 16\).
Then, multiply by the height: \(16\times7=112\).
Finally, divide by 2: \(\frac{112}{2}=56\).

Answer:

\(56\mathrm{cm}^2\)