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find the area of the shaded segment of the circle. the area of the shad…

Question

find the area of the shaded segment of the circle.
the area of the shaded segment is \\(\square\\) \\(\text{m}^2\\).
(round to the nearest tenth as needed.)

Explanation:

Step1: Find the central angle of the segment

The total angle in a circle is \(360^\circ\). The unshaded major arc is \(300^\circ\), so the central angle of the segment (\(\theta\)) is \(360^\circ - 300^\circ = 60^\circ\). Convert this to radians or use the formula for the area of a sector and triangle. We'll use degrees here.

Step2: Calculate the area of the sector with central angle \(60^\circ\)

The formula for the area of a sector is \(A_{sector} = \frac{\theta}{360^\circ} \times \pi r^2\), where \(r = 4\) m and \(\theta = 60^\circ\).

$$ A_{sector} = \frac{60^\circ}{360^\circ} \times \pi \times (4)^2 = \frac{1}{6} \times \pi \times 16 = \frac{8\pi}{3} \approx 8.3776 \text{ m}^2 $$

Step3: Calculate the area of the equilateral triangle (since two sides are radii and angle is \(60^\circ\), it's equilateral)

The formula for the area of an equilateral triangle with side length \(a\) is \(A_{triangle} = \frac{\sqrt{3}}{4} a^2\). Here, \(a = 4\) m.

$$ A_{triangle} = \frac{\sqrt{3}}{4} \times (4)^2 = \frac{\sqrt{3}}{4} \times 16 = 4\sqrt{3} \approx 6.9282 \text{ m}^2 $$

Step4: Calculate the area of the segment

The area of the segment is the area of the sector minus the area of the triangle.

$$ A_{segment} = A_{sector} - A_{triangle} \approx 8.3776 - 6.9282 \approx 1.4494 \approx 1.4 \text{ m}^2 $$

(rounded to the nearest tenth)

Answer:

\(1.4\)