Question

1. find the area of the parallelogram that has a base of $2\frac{1}{2}$ ft and a height of $1\frac{1}{4}$ ft.

$3\frac{3}{4}ft^{2}$
$4\frac{1}{6}ft^{2}$
$3\frac{1}{8}ft^{2}$
$3\frac{1}{4}ft^{2}$

Explanation:

Step1: Convert mixed numbers to improper fractions

The formula for the area of a parallelogram is \(A = b\times h\).
The base \(b = 2\frac{1}{2}=\frac{2\times2 + 1}{2}=\frac{5}{2}\) and the height \(h=1\frac{1}{4}=\frac{1\times4+ 1}{4}=\frac{5}{4}\).

Step2: Calculate the area

\(A=\frac{5}{2}\times\frac{5}{4}=\frac{25}{8}\).
Convert \(\frac{25}{8}\) to a mixed number: \(\frac{25}{8}=3\frac{1}{8}\) (since \(25\div8 = 3\) with a remainder of \(1\)).

Answer:

\(3\frac{1}{8}\text{ ft}^2\) (the third option)