Question

find the area.
area of \\( \triangle = ? \mathrm { in } ^ { 2 } \\)
area of \\( \square = \mathrm { in } ^ { 2 } \\)
remember:
\\( a _ { \delta } = \frac { 1 } { 2 } b h \\)
area of figure \\( = \mathrm { in } ^ { 2 } \\)

Explanation:

Step1: Calculate area of triangle

Use formula \(A_{\triangle}=\frac{1}{2}bh\). Here \(b = 12\) in, \(h=4\) in.
\(A_{\triangle}=\frac{1}{2}\times12\times4=24\) \(in^{2}\)

Step2: Calculate area of rectangle

Use formula \(A_{\square}=l\times w\). Here \(l = 12\) in, \(w = 9\) in.
\(A_{\square}=12\times9 = 108\) \(in^{2}\)

Step3: Calculate total area

Add areas of triangle and rectangle.
\(A=A_{\triangle}+A_{\square}=24 + 108=132\) \(in^{2}\)

Answer:

Area of \(\triangle=24\) \(in^{2}\)
Area of \(\square = 108\) \(in^{2}\)
Area of Figure \(=132\) \(in^{2}\)