QUESTION IMAGE
Question
find x, and then any unknown angles in the quadrilateral. this figure is not drawn to scale
Step1: Use the sum of interior angles of a quadrilateral
The sum of the interior angles of a quadrilateral is \(360^{\circ}\). So, \((x + 26)+x+(3x - 13)+(3x - 13)=360\).
Step2: Simplify the left - hand side of the equation
Combine like terms: \((x+x + 3x+3x)+(26-13 - 13)=360\), which simplifies to \(8x=360\).
Step3: Solve for \(x\)
Divide both sides of the equation \(8x = 360\) by \(8\), so \(x=\frac{360}{8}=45\).
Step4: Find the angles
- Angle \(P=(x + 26)^{\circ}\). Substitute \(x = 45\), then \(P=(45 + 26)^{\circ}=71^{\circ}\).
- Angle \(R=x^{\circ}=45^{\circ}\).
- Angle \(T=(3x - 13)^{\circ}\). Substitute \(x = 45\), then \(T=(3\times45-13)^{\circ}=(135 - 13)^{\circ}=122^{\circ}\).
- Angle \(S=(3x - 13)^{\circ}\). Substitute \(x = 45\), then \(S=(3\times45-13)^{\circ}=122^{\circ}\).
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\(x = 45\), \(\angle P=71^{\circ}\), \(\angle R = 45^{\circ}\), \(\angle T=122^{\circ}\), \(\angle S=122^{\circ}\)