Question

find all the zeros of the quadratic function.
$y = x^2 + 7x + 12$
if there is more than one zero, separate them with commas.
if there are no zeros, click on
one\.
zero(s):

Explanation:

Step1: Factor the quadratic

To find the zeros, set \( y = 0 \), so \( x^2 + 7x + 12 = 0 \). Factor the quadratic: we need two numbers that multiply to 12 and add to 7. Those numbers are 3 and 4. So, \( (x + 3)(x + 4) = 0 \).

Step2: Solve for x

Set each factor equal to zero: \( x + 3 = 0 \) or \( x + 4 = 0 \). Solving these gives \( x = -3 \) or \( x = -4 \).

Answer:

-3, -4