Question

find the absolute value.
|9 - 2i|
√?

Explanation:

Step1: Recall the formula for the absolute value of a complex number \( z = a + bi \), which is \( |z|=\sqrt{a^{2}+b^{2}} \).

For the complex number \( 9 - 2i \), we have \( a = 9 \) and \( b=- 2 \).

Step2: Substitute \( a = 9 \) and \( b = - 2 \) into the formula \( a^{2}+b^{2} \).

Calculate \( a^{2}+b^{2}=9^{2}+(-2)^{2}=81 + 4=85 \).

Answer:

\( 85 \) (So the value inside the square root is \( 85 \))