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Question
fill in the table using this function rule. y=4x−2 x y 2 3 7 8
Step1: Substitute x=2 into y=4x-2
$y = 4\times2 - 2 = 8 - 2 = 6$
Step2: Substitute x=3 into y=4x-2
$y = 4\times3 - 2 = 12 - 2 = 10$
Step3: Substitute x=7 into y=4x-2
$y = 4\times7 - 2 = 28 - 2 = 26$
Step4: Substitute x=8 into y=4x-2
$y = 4\times8 - 2 = 32 - 2 = 30$
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When \( x = 2 \), \( y = 6 \); when \( x = 3 \), \( y = 10 \); when \( x = 7 \), \( y = 26 \); when \( x = 8 \), \( y = 30 \)
So the completed table (from top to bottom for the \( y \)-values) is: 6, 10, 26, 30