Question

this figure consists of three squares and one rectangle. what is the area of the complete figure? 62 square inches 60 square inches 50 square inches 42 square inches

Explanation:

Step1: Calculate the area of the rectangle

The rectangle has length \(10\) in and width \(5 - 2-2 - 2=1\) in.
The area of a rectangle \(A_{r}=l\times w\), so \(A_{r}=10\times1 = 10\) square inches.

Step2: Calculate the area of one square

The side - length of each square is \(2\) in. The area of a square \(A_{s}=s^{2}\), so \(A_{s}=2^{2}=4\) square inches.

Step3: Calculate the total area of the three squares

Since there are three squares, \(A_{3s}=3\times A_{s}\). Substitute \(A_{s} = 4\) into the formula, we get \(A_{3s}=3\times4=12\) square inches.

Step4: Calculate the total area of the figure

The total area \(A = A_{r}+A_{3s}\). Substitute \(A_{r}=10\) and \(A_{3s}=12\) into the formula, we get \(A=10 + 12=62\) square inches.

Answer:

62 square inches