QUESTION IMAGE
Question
in the figure below, the two triangles are similar.
be corresponds to (da/ dn/ an)
en corresponds to (da/ dn/ an)
bn corresponds to (da/ dn/ an)
what is the scale factor applied to △ben to achieve △dan?
what is the scale factor applied to △dan to achieve △ben?
1. BE corresponds to which side?
In similar triangles \( \triangle BEN \) and \( \triangle DAN \), we match sides by their positions. \( BE \) is a side of \( \triangle BEN \), and \( DA \) is the corresponding side in \( \triangle DAN \) as they are the "outer" sides of each triangle (not adjacent to the common vertex \( N \)). Also, checking lengths: \( BE = 6 \), \( DA = 3 \), and \( 6/3 = 2 \), which is consistent with similarity. So \( BE \) corresponds to \( DA \).
\( EN \) is a side of \( \triangle BEN \) (length 8), and in \( \triangle DAN \), \( AN \) is the corresponding side (length 4). The ratio \( 8/4 = 2 \), which fits the similarity. Also, by the structure of the triangles (base sides from \( N \) to \( E \) and \( N \) to \( A \)), \( EN \) corresponds to \( AN \).
\( BN \) is a side of \( \triangle BEN \) (length 7), and in \( \triangle DAN \), \( DN \) is the corresponding side (length 3.5). The ratio \( 7/3.5 = 2 \), consistent with similarity. By the triangle structure (sides from \( B \) and \( D \) to \( N \)), \( BN \) corresponds to \( DN \).
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