Question

factor the difference of two squares. 4x^2 - 81 4x^2 - 81 =

Explanation:

Step1: Identify square - terms

We know that $4x^{2}=(2x)^{2}$ and $81 = 9^{2}$.

Step2: Apply difference - of - squares formula

The difference - of - squares formula is $a^{2}-b^{2}=(a + b)(a - b)$. Here, $a = 2x$ and $b=9$. So, $(2x)^{2}-9^{2}=(2x + 9)(2x - 9)$.

Answer:

$(2x + 9)(2x - 9)$