factor completely. (h^{2}+8h + 16)

$factor completely. (h^{2}+8h + 16)$

The expression $h^{2}+8h + 16$ is in the form of $a^{2}+2ab + b^{2}$, where $a = h$ and $2b=8$ (so $b = 4$).

The perfect - square formula is $a^{2}+2ab + b^{2}=(a + b)^{2}$. Substituting $a = h$ and $b = 4$ into the formula, we get $(h + 4)^{2}$.

$(h + 4)^{2}$