Question

factor completely. $18g^3 + 9g^2 + 8g + 4$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(18g^3 + 9g^2) + (8g + 4)$

Step2: Factor out GCF from each group

Factor out $9g^2$ from the first group and $4$ from the second group: $9g^2(2g + 1) + 4(2g + 1)$

Step3: Factor out the common binomial factor

Factor out $(2g + 1)$: $(9g^2 + 4)(2g + 1)$

Answer:

$(9g^2 + 4)(2g + 1)$