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factor completely. $g^2 + 9g + 14$

Question

factor completely.
$g^2 + 9g + 14$

Explanation:

Step1: Find two numbers

We need two numbers that multiply to \(14\) and add up to \(9\). The numbers \(2\) and \(7\) work because \(2\times7 = 14\) and \(2 + 7=9\).

Step2: Factor the quadratic

Using the numbers found, we can factor \(g^{2}+9g + 14\) as \((g + 2)(g + 7)\).

Answer:

\((g + 2)(g + 7)\)