expand the expression to a polynomial in standard form: (2x + 5)(x - 2)(2x + 3)

Question

Accepted Answer

# Explanation:
## Step1: Multiply first two factors
Multiply $(2x + 5)$ and $(x - 2)$ using distributive property (FOIL method).
$$
\begin{align*}
(2x + 5)(x - 2)&=2x\times x+2x\times(-2)+5\times x + 5\times(-2)\
&=2x^{2}-4x + 5x-10\
&=2x^{2}+x - 10
\end{align*}
$$
## Step2: Multiply the result with third factor
Now multiply $(2x^{2}+x - 10)$ with $(2x + 3)$
$$
\begin{align*}
&(2x^{2}+x - 10)(2x + 3)\
=&2x^{2}\times(2x)+2x^{2}\times3+x\times(2x)+x\times3-10\times(2x)-10\times3\
=&4x^{3}+6x^{2}+2x^{2}+3x-20x - 30\
=&4x^{3}+(6x^{2}+2x^{2})+(3x - 20x)-30\
=&4x^{3}+8x^{2}-17x - 30
\end{align*}
$$
# Answer:
$4x^{3}+8x^{2}-17x - 30$

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Question

Explanation:

Step1: Multiply first two factors

Step2: Multiply the result with third factor

Answer: