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for exercises 7 through 26, find the area under the standard normal dis…

Question

for exercises 7 through 26, find the area under the standard normal distribution curve.

  1. between ( z = 0 ) and ( z = 0.98 )

Explanation:

Step1: Use the standard normal table

The area under the standard normal curve between \(z = 0\) and \(z=0.98\) can be found using the standard - normal distribution table. The standard - normal distribution table gives the cumulative area from the left up to a given \(z\) - value.
The cumulative area up to \(z = 0\) is \(P(Z\leq0)=0.5\) (by the property of the standard normal distribution, since the standard normal distribution \(N(0,1)\) is symmetric about \(z = 0\)).
The cumulative area up to \(z=0.98\) is \(P(Z\leq0.98)\). Looking up \(z = 0.98\) in the standard - normal table (where the table has rows for the integer and first decimal place of \(z\) and columns for the second decimal place of \(z\)). For \(z=0.98\), we find \(P(Z\leq0.98)=0.8365\)

Step2: Calculate the area between \(z = 0\) and \(z = 0.98\)

We use the formula \(P(0<Z<0.98)=P(Z < 0.98)-P(Z < 0)\)

Substitute the values we found from the table: \(P(0<Z<0.98)=0.8365 - 0.5\)

$$P(0

Answer:

\(0.3365\)