Question

in exercises 23 through 44 convert each of the following units. express answers to three significant digits.

1. 594 to w
2. 6.50 mω to kω

25 0.0000453 a to μa

1. 5,670,000 v to mv
2. 670 pf to nf
3. 0.0560 ms to μs
4. 560 mm to cm
5. 0.000593 km to cm
6. 3.20 × 10⁴ v to kv

Explanation:

Step1: Recall unit - conversion factors

Use the following conversion factors: $1\ M\Omega = 10^{3}\ k\Omega$, $1\ A=10^{6}\ \mu A$, $1\ MV = 10^{6}\ V$, $1\ nF = 10^{3}\ pF$, $1\ ms=10^{3}\ \mu s$, $1\ cm = 10\ mm$, $1\ km = 10^{5}\ cm$, $1\ kV=10^{3}\ V$.

Step2: Solve problem 23

The value $594$ is already in watts (W), so the answer is $594\ W$.

Step3: Solve problem 24

We know that $1\ M\Omega = 10^{3}\ k\Omega$. So, $6.50\ M\Omega=6.50\times10^{3}\ k\Omega = 6500\ k\Omega$.

Step4: Solve problem 25

Since $1\ A = 10^{6}\ \mu A$, then $0.0000453\ A=0.0000453\times10^{6}\ \mu A = 45.3\ \mu A$.

Step5: Solve problem 26

Since $1\ MV = 10^{6}\ V$, then $5670000\ V=\frac{5670000}{10^{6}}\ MV = 5.67\ MV$.

Step6: Solve problem 27

Since $1\ nF = 10^{3}\ pF$, then $670\ pF=\frac{670}{10^{3}}\ nF = 0.670\ nF$.

Step7: Solve problem 28

Since $1\ ms = 10^{3}\ \mu s$, then $0.0560\ ms=0.0560\times10^{3}\ \mu s = 56.0\ \mu s$.

Step8: Solve problem 29

Since $1\ cm = 10\ mm$, then $560\ mm=\frac{560}{10}\ cm = 56.0\ cm$.

Step9: Solve problem 30

Since $1\ km = 10^{5}\ cm$, then $0.000593\ km=0.000593\times10^{5}\ cm = 59.3\ cm$.

Step10: Solve problem 31

Since $1\ kV = 10^{3}\ V$, then $3.20\times10^{4}\ V=\frac{3.20\times10^{4}}{10^{3}}\ kV=32.0\ kV$.

Answer:

1. $594\ W$
2. $6500\ k\Omega$
3. $45.3\ \mu A$
4. $5.67\ MV$
5. $0.670\ nF$
6. $56.0\ \mu s$
7. $56.0\ cm$
8. $59.3\ cm$
9. $32.0\ kV$