Question

exam lesson name: energy conversions
exam number: 700697rr
exam guidelines
exam instructions
question 19 of 20 :
select the best answer for the question.

1. a 6.7 kg object moves with a velocity of 8 m/s. whats its kinetic energy?

a. 53.6 j
b. 214.4 j
c. 26.8 j
d. 167.5 j
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Explanation:

Step1: Recall kinetic energy formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is mass in kilograms and $v$ is velocity in meters per second.

Step2: Substitute values into formula

Given $m = 6.7\ \text{kg}$ and $v = 8\ \text{m/s}$. Substitute these into the formula:
$KE=\frac{1}{2}\times6.7\times8^2$
First, calculate $8^2 = 64$. Then, $\frac{1}{2}\times6.7 = 3.35$. Now multiply $3.35\times64$.
$3.35\times64 = 214.4$

Answer:

B. 214.4 J