Question

exam
evaluate each expression.

1. $(4 + 3)(6)$

a) 42 b) 41
c) 48 d) 38

1. (6)(

a)
c)

1. $(9 \div 3)^2 - 2$

a) 7 b) 9
c) 11 d) 2
4)

1. $((6)(2)) \div (3 + 2 - 3)$

a) 6 b) 9
c) 2 d) 1
evaluate each using the values given.

1. $c^2 - b$; use $b = 5$, and $c = 3$
2. $4x - (y + z)$; use $x = 5$, $y = 6$, and $z = 2$

Explanation:

Problem 1: \((4 + 3)(6)\)

Step 1: Calculate inside the first parentheses

First, we add the numbers inside the parentheses \((4 + 3)\). So, \(4 + 3 = 7\).

Step 2: Multiply the result by 6

Now we multiply the result from step 1 by 6. So, \(7\times6 = 42\).

Step 1: Calculate inside the parentheses

First, we perform the division inside the parentheses \((9\div3)\). So, \(9\div3 = 3\).

Step 2: Square the result

Next, we square the result from step 1. So, \(3^{2}=9\).

Step 3: Subtract 2 from the result

Finally, we subtract 2 from the result of step 2. So, \(9 - 2 = 7\).

Step 1: Calculate the numerator

First, we calculate the product in the numerator \((6)(2)\). So, \(6\times2 = 12\).

Step 2: Calculate the denominator

Next, we calculate the expression in the denominator \(3 + 2 - 3\). First, \(3+2 = 5\), then \(5 - 3 = 2\).

Step 3: Divide the numerator by the denominator

Finally, we divide the result from step 1 by the result from step 2. So, \(12\div2 = 6\).

Answer:

A) 42

Problem 3: \((9\div3)^{2}-2\)