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Question
evaluate the following expression for (a) \\(x = 4\\) and \\(y = 1\\) and (b) \\(x = 1\\) and \\(y = 3\\).
\\\frac{4x + 8y}{5x + 8y}\\
(a) for \\(x = 4\\) and \\(y = 1\\), \\\\ \frac{4x + 8y}{5x + 8y} = \square
(type an integer or a simplified fraction.)
Substitute the given values into the expression
$$
\text{For } x = 4 \text{ and } y = 1:
$$
$$
\frac{4(4) + 8(1)}{5(4) + 8(1)}
$$
Simplify the numerator and denominator
$$
\text{Numerator: } 4(4) + 8(1) = 16 + 8 = 24
$$
$$
\text{Denominator: } 5(4) + 8(1) = 20 + 8 = 28
$$
$$
\text{Fraction: } \frac{24}{28}
$$
Reduce the fraction to simplest form
$$
\frac{24 \div 4}{28 \div 4} = \frac{6}{7}
$$
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(a) For \(x = 4\) and \(y = 1\), \(\frac{4x + 8y}{5x + 8y} =\) <blank>\(\frac{6}{7}\)</blank>